Smallest Number with Remainders
Problem
Determine the smallest number between 300 and 400 which when divided by 2, 3, 4, 5, 6 leaves the remainder 1, 2, 3, 4, 5 respectively.
Options:
A) 349
B) 329
C) 339
D) 359
Solution
The pattern is: number + 1 is divisible by 2, 3, 4, 5, 6.
LCM(2, 3, 4, 5, 6) = 60.
Number = 60k - 1. For k = 6: 360 - 1 = 359. 300 < 359 < 400 ✓.