Aptitude
1 sections, 11 questions
In an exam, a student scored 60% marks and failed by 12 marks. Another student scored 75% marks and got 18 marks more than the passing marks. Find the maximum marks.
Let maximum marks = M and passing marks = P
60% of M + 12 = P → 0.6M + 12 = P
75% of M - 18 = P → 0.75M - 18 = P
Equating:
0.6M + 12 = 0.75M - 18
30 = 0.15M
M = 200
Fill in the blank spaces in the series: 48, 45, 40, 33, 24, ___, ___
Differences between consecutive terms: -3, -5, -7, -9
This follows the pattern of decreasing by consecutive odd numbers.
Next difference = -11 → 24 - 11 = 13
Next difference = -13 → 13 - 13 = 0
The average age of a class of 30 students is 15 years. If the teacher's age is included, the average becomes 16 years. Find the teacher's age.
Total age of 30 students = 30 × 15 = 450
Total age including teacher = 31 × 16 = 496
Teacher's age = 496 - 450 = 46 years
Two friends A and B start running in opposite directions on a circular track of length 350 meters, starting from diametrically opposite points. They first meet after A has run 100 meters. Find how far B has run by the time they first meet.
Since A and B start at diametrically opposite points and run towards each other, together they cover half the track by the time they first meet.
Half the track = 350/2 = 175 meters
Distance covered by B = 175 - 100 = 75 meters
A bag contains coins in the ratio 3:4:5 for one-rupee, two-rupee, and five-rupee coins respectively. If the total value of coins is ₹1,440, find the number of two-rupee coins.
Let the number of coins be 3x, 4x, 5x.
Value = 3x(1) + 4x(2) + 5x(5) = 3x + 8x + 25x = 36x
36x = 1440
x = 40
Number of two-rupee coins = 4x = 4 × 40 = 160
Yard is to Inch as Quart is to ?
Options: (a) Oil (b) Ounce (c) Liquid (d) None of these
A Yard is a larger unit of length that is divided into smaller units called Inches.
Similarly, a Quart is a larger unit of volume that is divided into smaller units called Ounces.
In a certain code, GUEST is written as 53@$2 and MEAN is written as 6@4#. How is SAME written in that code?
From GUEST = 53@, T=2
From MEAN = 6@4#: M=6, E=@, A=4, N=#
SAME → S=46@
A is the son of C; C and Q are sisters; Z is the mother of Q and P is the son of Z. Which of the following statements is true?
Options: (a) P is father of A (b) P is brother of C (c) A is son of Z (d) Q is sister of A
Since P is Z's son and C is Z's daughter, P is C's brother.
Look carefully for the pattern and choose which pair of numbers comes next: 7, 9, 66, 12, 14, 66, 17, ___, ___
The sequence follows a repeating pattern: two numbers increasing by intervals, followed by a constant "66".
7, 9 (diff 2), 66, 12, 14 (diff 2), 66, 17, 19 (diff 2), 66
Find the odd one among the following binary numbers:
(a) 1011 (b) 1101 (c) 1111 (d) 10001 (e) 111
Convert each to decimal:
1011 = 11 (odd number of set bits: 3 → odd)
1101 = 13 (3 set bits → odd)
1111 = 15 (4 set bits → even)
10001 = 17 (2 set bits → even)
111 = 7 (3 set bits → odd)
Checking another pattern - count of 1s: 1011(3), 1101(3), 1111(4), 10001(2), 111(3)
1111 has 4 set bits while all others have an odd count of set bits.
Statements: 1. Some buds are leaves. 2. Some leaves are red.
Conclusions: I. Some buds are red. II. Some leaves are not buds.
Which conclusion(s) follow?
From "Some buds are leaves" and "Some leaves are red", we cannot definitively conclude "Some buds are red" because the "leaves" that are red may not overlap with the "leaves" that are buds.
Conclusion II also cannot be definitively derived from the given statements using strict syllogism rules.